(c^2+9c+14)/(c+7)=0

Solution for (c^2+9c+14)/(c+7)=0 equation:

(c^2+9c+14)/(c+7)=0


Domain of the equation: (c+7)!=0

We move all terms containing c to the left, all other terms to the right

c!=-7

c∈R


We multiply all the terms by the denominator


(c^2+9c+14)=0

We get rid of parentheses

c^2+9c+14=0

a = 1; b = 9; c = +14;
Δ = b2-4ac
Δ = 92-4·1·14
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*1}=\frac{-14}{2}
=-7
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*1}=\frac{-4}{2}
=-2
$